(x^2)+28x-704=0

Solution for (x^2)+28x-704=0 equation:

(x^2)+28x-704=0

a = 1; b = 28; c = -704;
Δ = b2-4ac
Δ = 282-4·1·(-704)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-60}{2*1}=\frac{-88}{2}
=-44
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+60}{2*1}=\frac{32}{2}
=16
$